Question

Calculate the propagation constant of a wave with impedance and admittance given by 32 and 12 respectively. (a) 19.6 (b) 17.6 (c) 15.6 (d) 13.6 This question was posed to me in a national level competition. I need to ask this question from Intrinsic Impedance and Propagation Constant topic in section Transmission Lines of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

Answer 1

The correct option is (a) 19.6 Best explanation: The propagation constant is given by γ = √(ZY), where Z is the impedance and Y is the admittance. On substituting for Z = 32 and Y = 12, we get γ = 19.6 units.