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The propagation constant of a wave with attenuation and phase constant given by 2 and 3 respectively is (a) 2 – 3j (b) 3 – 2j (c) 2 + 3j (d) 3 + 2j I had been asked this question in examination. This key question is from Transmission Line Secondary Parameters topic in division Transmission Lines of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Right answer is (c) 2 + 3j The explanation: The propagation constant is given by γ = α + jβ. Given that α = 2 and β = 3. Thus we get the propagation constant as γ = 2 + 3j.

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