Question

Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×10^8 m/s(in 10^-8 order) (a) 0.5 (b) 72 (c) 4 (d) 36 This question was posed to me during an interview for a job. The query is from Lossy and Lossless Dielectrics in chapter EM Wave Propagation of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

Answer 1

Correct answer is (c) 4 The best explanation: The phase constant is given by β = ω√(με), where ω is the frequency in rad/s and 1/√(με) is the velocity of wave. On substituting √(με) = 3×10^8 and ω = 12, we get β = 12/(3×10^8) = 4 x 10^-8m/s.