Correct Answer - 0.061M
First case
W2=36g,P=4.98bar
,
Mw2(
glucose )=180,V=1L,
P=
n
V
RT
4.98=
36
180×1
RT…..(i)
Second case
1.52=CRT….(ii)
Dividing Eq.(i)
by Eq.(ii)
, we get
4.98
1.52
=
0.2RT
CRT
C=
0.2×1.52
4.98
=0.61M
The concentration of solution =0.061M