Correct Answer - Mw2=41.35gmol-1
p∘=1atm=1.013bar,pS=1.004bar
W2=2g,Wsol=100g,W1=100-2=98g
For dilute solution , use the relation :
p∘-pS
P∘
=
n2
n1+n2
=
n2
n1
=
W2/Mw2
W1/Mw1
(1.013-1.004)bar
1.013bar
=
2g
Mw2
×
18gmol-1
98g
Mw2=
2×18
98
×
1.013
0.009
gmol-1
=41.35gmol-1