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Determine the amount of `CaCl_(2)` (i = 2.47) dissolved in 2.5 L of water sucjh that its osmotic pressure is 0.75 atm at `27^(@)C`.

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Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 L of water sucjh that its osmotic pressure is 0.75 atm at 27∘C . Select the correct answer from above options

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Correct Answer - W2=3.42g Mw of CaCl2=40+2×35.5=111.0gmol-1 π=iMRT=i× n V RT (or) n= π×V i×R×T = 0.75atm×2.5L 2.47×0.0821LatmK-1mol-1×300K =0.0308mol ∴ Weight of CaCl2 dissolved =n×Mw =0.0308×111.0g 3.42g

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