Question

In bag A, no of yellow colored balls are Y and no. of green colored balls balls are g,Number of green colored balls are 4 more than the number of yellow colored balls , when one ball is picked at random then the probaility of getting black color ball is 15 13 . the value of Y is 18 2 11 % less than g. In bag B, number of yellow colored balls is 22 2 9 % more than that of bag A, If two balls are picked at random from bag B then the probability of getting both green color ball is 4 37 . Total number of balls in bag B is 75. In bag C, the ratio of number of green colored balls and number of black colored balls is 7:5 Total number of green and black colored balls is 36, If one ball is picked at random then the probability of getting one yellow ball is 7 13 . If x number of yellow balls from bag B are taken placed into bag A and 20% of black balls bag A are taken and placed into in bag B.If pick one ball from bag B then the probability that the ball is of black color is 11 26 , then find the value of x ? A. 5 B. 6 C. 3 D. 2 Select the correct answer from above options

Answer 1

Correct Answer - D After replacement → Yellow no. of balls in bag B=22x Black no . Of balls in bag B=28+5=33 Green no. of balls in bag B=25 then , 33 22-x+33+25 = 11 26 33 80-x = 11 26 78=80-x x=2