Correct Answer - `"Mean "=(4)/(3), "variance "=(5)/(9)`
`P(X=0)=(""^(5)C_(3))/(""^(9)C_(3))=(5)/(42),P(X=1)=((""^(4)C_(1)xx""^(5)C_(2)))/(""^(9)C_(3))=(10)/(21)`
`P(X=2)=((""^(4)C_(2)xx""^(5)C_(1)))/(""^(9)C_(3))=(5)/(14), P(X=3)=(""^(4)C_(3))/(""^(9)C_(3))=(1)/(21).`