Question

In bag A there are 8 red balls ,X green balls and 6 yellow balls,probability of drawing one green ball from bag A is 3/5. bag B there are (X-3) red balls, (X-9) green balls and 6 yellow balls ,2 balls are drawn from bag B. Find the porbability that both the balls are red colour ? A. 12/63 B. 13/70 C. 14/75 D. 17/70 Select the correct answer from above options

Answer 1

Correct Answer - D Probability of drawing one green ball ⇒ x 14+x = 3 5 ⇒5x=42+3x ⇒x=2I ⇒ green balls = 21 In Bag B Red balls =(x-3)=(21-3)=18 Green balls =(x-9)=(21-9)=12 Yellow balls = 6 ∴ Required probability = 18C2 36C2 = 18×17 36×85 = 17 70