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If potential V = 20/(x^2 + y^2). The electric field intensity for V is (a) /(x^2 + y^2)^2. State True/False. (b) True (c) False I got this question during an interview. My question is based upon Relation of E,D,V in chapter Electrostatic Fields of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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The correct option is (a) /(x^2 + y^2)^2. State True/False. The explanation is: E = -Grad (V) = -Grad(20/(x^2 + y^2)) = -(-40x i /(x^2 + y^2)^2 – 40(y j)/(x^2 + y^2)^2) = 40(x i + y j)/(x^2 + y^2)^2. Thus the statement is true.

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