Question

Find the vector potential when the field intensity 60x^2 varies from (0,0,0) to (1,0,0). (a) 120 (b) -20 (c) -180 (d) 60 I had been asked this question at a job interview. The above asked question is from Magnetic Vector Potential in division Magnetostics of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

Answer 1

Right answer is (b) -20 The explanation is: The field intensity H = -Grad(V). To get V, integrate H with respect to the variable. Thus V = -∫H.dl = -∫60x^2 dx = -20x^3 as x = 0->1 to get -20.