Question

A current I given by I = – 8 + 6\sqrt{2} (sin (ωt + 30°)) A is passed through three meters. The respective readings (in ampere) will be? (a) 8, 6 and 10 (b) 8, 6 and 8 (c) – 8, 10 and 10 (d) -8, 2 and 2 I got this question during an interview. I'd like to ask this question from Problems Involving Standard Time Functions in portion Application of the Laplace Transform in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct choice is (c) – 8, 10 and 10 For explanation: PMMC instrument reads only DC value and since it is a centre zero type, so it will give – 8 values. So, rms = \sqrt{8^2 + \left(\frac{6\sqrt{2}}{\sqrt{2}})^2\right)} = 10 A Moving iron also reads rms value, so its reading will also be 10 A.