Question

Given two voltages, V1 = sin (ωt + 60°) and V2 = cos (ωt). Which of the following is correct? (a) V1 is leading V2 by 15° (b) V1 is leading V2 by 30° (c) V2 is leading V1 by 60° (d) V2 is leading V1 by 30° This question was addressed to me during an interview for a job. My question is from Advanced Problems on Network Theorems topic in portion Useful Theorems in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct answer is (c) V2 is leading V1 by 60° For explanation I would say: Given that, V1 = sin (ωt + 30°) and V2 = cos (ωt) Now, V2 can be written as, V2 = sin (ωt + 90°). Hence, V2 is leading V1 by (90 – 30) = 60°.