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Current I = – 1 + \sqrt{2} (sin (ωt + 60°)) A is passed through three meters. The respective readings will be? (a) \sqrt{2} A, \sqrt{2} A and 1 A (b) 1 A, \sqrt{2} A and 1 A (c) – 1 A, \sqrt{2} A and \sqrt{2} A (d) -1 A, 1 A and 1 A I got this question in final exam. My question comes from Advanced Problems on Filters in division Filters and Attenuators of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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The correct option is (c) – 1 A, \sqrt{2} A and \sqrt{2} A The explanation: We know that a PMMC instrument reads only DC value and since it is a centre zero type, so it will give – 1. So, rms = \sqrt{1^2 + (\frac{\sqrt{2}}{\sqrt{2}})^2} = \sqrt{2} A Moving iron also reads rms value, so its reading will also be \sqrt{2} A.

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