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Obtain the admittance of the last two elements in the parallel combination after transformation in the circuit shown below. (a) 1+s (b) 2+s (c) 3+s (d) 4+s This question was posed to me during an internship interview. My doubt is from Series and Parallel Combination of Elements topic in section S-Domain Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Right choice is (d) 4+s To explain I would say: The term admittance is defined as the inverse of impedance. The admittance of capacitor is 1/s and the admittance of resistor is 1/4 mho. So the admittance of the last two elements in the parallel combination is Y1(s) = 4 + s.

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