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The series combination of the last elements after replacing 1/s and 1/4Ω with 1/(S+4) is?

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The series combination of the last elements after replacing 1/s and 1/4Ω with 1/(S+4) is? (a) (3s+4)/2s(s-4) (b) (3s-4)/2s(s-4) (c) (3s+4)/2s(s+4) (d) (3s-4)/2s(s+4) The question was posed to me in an interview for job. Enquiry is from Series and Parallel Combination of Elements topic in portion S-Domain Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Correct answer is (c) (3s+4)/2s(s+4) To explain: We got the impedance of last two elements in parallel combination as Z1(s) = 1/(s+4) and now the impedance of capacitor is 1/2s. So the series combination of the last elements is Z2(s) = 1/2s+1/(s+4) = (3s+4)/2s(s+4).

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