Question

Obtain the transform impedance of the network shown below. (a) (6s-8)/(4s^2+19s-4) (b) (6s+8)/(4s^2+19s+4) (c) (6s+8)/(4s^2-19s+4) (d) (6s-8)/(4s^2+19s+4) I have been asked this question during an interview. This key question is from Series and Parallel Combination of Elements topic in portion S-Domain Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Right option is (b) (6s+8)/(4s^2+19s+4) Explanation: The term impedance is the inverse of the term admittance. We got admittance as Y2(s) = (4s^2+19s+4)/(6s+8). So the transform impedance of the network is Z (s) = 1/Y2(s) = (6s+8)/(4s^2+19s+4).