Question

The expression of current flowing in a series equalizer is? (a) Vmax/√((Ro)^2+(X1)^2) (b) Vmax/√((2Ro)^2+(X1)^2) (c) Vmax/√((2Ro)^2+(2X1)^2) (d) Vmax/√((Ro)^2+(2X1)^2) I got this question at a job interview. Enquiry is from Series Equalizer topic in portion Filters and Attenuators of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct option is (c) Vmax/√((2Ro)^2+(2X1)^2) The best explanation: When the equalizer is connected, the expression of current flowing in a series equalizer is I1 = Vmax/√((2Ro)^2+(2X1)^2) where Vmax is voltage applied to the network and Ro is resistance of the load as well as source and 2X1 is the reactance of the equalizer.