Question

What is the power at the load of a series equalizer? (a) [Vmax^2/(Ro^2+X1^2)]Ro (b) [Vmax^2/(2(Ro^2+X1^2))]Ro (c) [Vmax^2/(3(Ro^2+X1^2))]Ro (d) [Vmax^2/(4(Ro^2+X1^2))]Ro I had been asked this question during an interview. My question is based upon Series Equalizer in portion Filters and Attenuators of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct choice is (d) [Vmax^2/(4(Ro^2+X1^2))]Ro To elaborate: The power at the load of a series equalizer is P=(Vmax/√((2Ro)^2+(2X1)^2))^2 Ro = [Vmax^2/(4(Ro^2+X1^2))]Ro.