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Determine the current flowing in the ammeter having 1Ω internal resistance connected in series with the 3Ω resistor as shown in the below circuit. (a) 0.91 (b) 0.92 (c) 0.93 (d) 0.94 The question was asked at a job interview. My question is based upon Compensation Theorem topic in chapter Useful Theorems in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Right option is (c) 0.93 Best explanation: Current through 3Ω resistor = 1.11A. So voltage drop across 1Ω resistor = 1.11×1 = 1.11V. Now the circuit can be modified as Now current through 3Ω resistor = 0.17A. This current is opposite to the current calculated before. So ammeter reading = (1.11-0.17) = 0.94A.

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