Correct Answer - 0.67M
Let us suppose that the mass of solution is 100g
Since solution is 10%
glucose , therefore the mass of solvent is 100-10=90g
Molar mass of glucose, C6H12O6=72+12+96
=180gmol
m=
W2×1000
Mw2×W1
=
10×1000
180×90
=0.617m
Moles of water=
90
18
=5
Moles of glucose =
10
180
=0.055mol
Mole fraction of glucose (CHMi2)=
0.055
5+0.55
=0.01
Mole fraction of water (CHMi1)=1-0.01=0.99
Vsol=
Wsol
dsol
=
100
1.2
=83.33mL
M=
W2×1000
Mw2×VsolinmL
=
n2×1000
VsolinmL
=
0.055×1000
83.33
=0.67M