Correct Answer - Rate of formation of Y
will increase by 9 times
For second order kinetics, the rate law is :
r1=Rate1=k[X]2…..(i)
If the concentration of X
is increased to 3 times, i.e.,[3X],
then rate (r2)
will be
r2=k[3X]2
9k[X]2….(ii)
∴
r2
r1
=
9k[X]2
k[X]2
=9
∴r2=9r1
Thus, the rate of reaction will becomes 9 times. Hence, the rate of formation of Y
will increases 9 times.