(i) the value of k
We know that,
Sum of the probabilities = 1
⇒ k = 0.02
(ii) To find: E(X)
The probability distribution of X is:
Therefore,
μ = E(X)
(iii) To find: Standard deviation of X
We know that,
Var(X) = E(X2) – [E(X)]2
= ΣX2P(X) – [Σ{XP(X)}]2
= [2k + 12k + 36k + 80k + 250k + 432k + 686k +0] – [5.2]2 = 1498k – 27.04
= 29.96 – 27.04
= 2.92
We know that,
standard deviation of X = √Var(X) = √2.92 = 1.7088
≅ 1.7