Given: A pair of dice is thrown
Required to find: Probability that the total of numbers on the dice is greater than 10
First let’s write the all possible events that can occur
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6),
It’s seen that the total number of events is 62 = 36
Favourable events i.e. getting the total of numbers on the dice greater than 10 are (5, 6), (6, 5) and (6, 6).
So, the total number of favourable events i.e. getting the total of numbers on the dice greater than 10 is 3.
We know that, Probability = Number of favourable outcomes/ Total number of outcomes
Thus, the probability of getting the total of numbers on the dice greater than 10 = 3/36 = 1/12.
