A bag contains 3 red balls, 5 black balls.
Totally there are 8 balls.
∴ n(S) = 8
i) Possibility that the red ball drawn, n(E) = 3
∴ Probability, P(E) =
n(E)
n(S)
=
3
8
(ii) Possibility that the 1 black ball drwn is n(F) = 5
∴ Probability, P(F) =
n(F)
n(S)
=
5
8