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What is the probability that an ordinary year has 53 Sundays? Select the correct answer from above options

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Given: A year which includes 52 weeks and one day. By using the formula, P (E) = favourable outcomes / total possible outcomes So, we now have to determine the probability of that one day being Sunday Total number of possible outcomes is 7 n(S) = 7 E = {M, T, W, T, F, S, SU} n (E) = 1 P (E) = n (E) / n (S) = 1/7

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