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Find the probability of 53 Sundays and 53 Mondays in a leap year. A. 2 7 B. 4 7 C. 3 7 D. 1 7 Select the correct answer from above options

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Correct Answer - C A leap year consists of 366 days comprising of 52 weeks and 2 days. There are 7 possibilities for these 2 extra days viz., (i) Sunday, Monday (ii) Monday, Tuesday (iii) Tuesday, Wednesday (iv) Wednesday, Thursday (v) Thursday, Friday (vi) Friday, Saturday (vii) Saturday, Sunday. Let us consider two events : A : The leap year contains 53 Sundays B : The leap year contains 53 Mondays. We have, P(A)= 2 7 ,P(B)= 2 7 ,P(A∩B)= 1 7 Required probability =P(A∪B) =P(A)+P(B)-P(A∩B)= 2 7 + 2 7 - 1 7 = 3 7

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