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A sample space consists of 9 elementary outcomes e1, e2, ..., e9 whose probabilities are P(e1) = P(e2) = .08, P(e3) = P(e4) = P(e5) = .1 P(e6) = P(e7) = .2, P(e8) = P(e9) = .07 Suppose A = {e1, e5, e8}, B = {e2, e5, e8, e9} (a) Calculate P (A), P (B), and P (A ∩ B) (b) Using the addition law of probability, calculate P (A ∪ B) (c) List the composition of the event A ∪ B, and calculate P (A ∪ B) by adding the probabilities of the elementary outcomes. (d) Calculate P (\(\overline B\)) from P (B), also calculate P (\(\overline B\)) directly from the elementary outcomes of \(\overline B\). Select the correct answer from above options

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Given that: S = {e1, e2, e3, e4, e5, e6, e7, e8, e9} A = {e1, e5, e8} and B = {e2, e5, e8, e9} P(e1) = P(e2) = .08, P(e3) = P(e4) = P(e5) = .1 P(e6) = P(e7) = .2, P(e8) = P(e9) = .07 (a) To find: P(A), P(B) and P(A ⋂ B) A = {e1, e5, e8} P(A) = P(e1) + P(e5) + P(e8) ⇒ P(A) = 0.08 + 0.1 + 0.07 [given] ⇒ P(A) = 0.25 B = {e2, e5, e8, e9} P(B) = P(e2) + P(e5) + P(e8) + P(e9) ⇒ P(B) = 0.08 + 0.1 + 0.07 + 0.07 [given] ⇒ P(B) = 0.32 Now, we have to find P(A ⋂ B) A = {e1, e5, e8} and B = {e2, e5, e8, e9} ∴ A ⋂ B = {e5, e8} ⇒ P(A ⋂ B) = P(e5) + P(e8) = 0.1 + 0.07 = 0.17 (b) To find: P(A ⋃ B) By General Addition Rule: P(A ⋃ B) = P(A) + P(B) – P(A ⋂ B) from part (a), we have P(A) = 0.25, P(B) = 0.32 and P(A ⋂ B) = 0.17 Putting the values, we get P(A ⋃ B) = 0.25 + 0.32 – 0.17 = 0.40 (c) A = {e1, e5, e8} and B = {e2, e5, e8, e9} ∴ A ⋃ B = {e1, e2, e5, e8, e9} ⇒ P(A ⋃ B) = P(e1) + P(e2) + P(e5) + P(e8) + P(e9) = 0.08 +0.08 + 0.1 + 0.07 + 0.07 = 0.40 = 0.08 + 0.1 + 0.1 + 0.2 + 0.2 [given] = 0.68

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