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In a non-leap year, the probability of having 53 Tuesdays or 53 Wednesdays is A. 1/7 B. 2/7 C. 3/7 D. none of these

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In a non-leap year, the probability of having 53 Tuesdays or 53 Wednesdays is A. 1/7 B. 2/7 C. 3/7 D. none of these Select the correct answer from above options

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B. 2/7 Explanation: We know that in a non-leap year, there are 365 days and we know that there are 7 days in a week ∴ 365 ÷ 7 = 52 weeks + 1 day This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday ∴ Total Outcomes = 7 If this day is a Tuesday or Wednesday, then the year will have 53 Tuesday or 53 Wednesday. ∴P (non-leap year has 53 Tuesdays or 53 Wednesdays) = 1/7 + 1/7 = 2/7 Hence, the correct option is (B).

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