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If P(A) = 2/5, P(B) = 3/10 and P(A ∩ B) = /|5, the P(A′|B′).P(B′|A′) is equal to A. 5/6 B. 5/7 C. 25/42 D. 1

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If P(A) = 2/5, P(B) = 3/10 and P(A ∩ B) = /|5, the P(A′|B′).P(B′|A′) is equal to A. 5/6 B. 5/7 C. 25/42 D. 1 Select the correct answer from above options

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We have, [∵P(A’ ∩ B’) = P[(A ∪ B)’]= 1 – P(A ∪ B)] Hence, the correct option is C

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