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A and B throw a pair of dice alternately. A wins the game if he gets a total of 6 and B wins if she gets a total of 7. It A starts the game, find the probability of winning the game by A in third throw of the pair of dice. Select the correct answer from above options

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Let’s take A1 to be the event of getting a total of 6 A1 = {(2, 4), (4, 2), (1, 5), (5, 1), (3, 3)} And, B1 be the event of getting a total of 7 B1 = {(2, 5), (5, 2), (1, 6), (6, 1), (3, 4), (4, 3)} Let P(A1) is the probability, if A wins in a throw = 5/36 And P(B1) is the probability, if B wins in a throw = 1/6 Therefore, the required probability of wining A in his third throw

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