Question

The probability distribution of a random variable x is given as under: where k is a constant. Calculate (i) E(X) (ii) E (3X2) (iii) P(X ≥ 4) Select the correct answer from above options

Answer 1

The probability distribution of random variable X is given by: We know that So, k + 4k + 9k + 8k + 10k + 12k = 1 44k = 1 k = 1/44 (i) E(X) = 1 x k + 2 x 4k + 3 x 9k + 4 x 8k + 5 x 10k + 6 x 12k = k + 8k + 27k + 32k + 50k + 72k = 190k = 190 x 1/44 = 95/22 = 4.32 (approx.) (ii) E(X2) = 3(k + 4 x 4k + 9 x 9k + 16 x 8k + 25 x 10k + 36 x 12k) = 3(k + 16k + 81k + 128k + 250k + 432k) = 3(908k) = 3 x 908 x 1/44 = 2724/44 = 61.9 (approx.) (iii) P(X ≥ 4) = P(X = 4) + P(X = 5) + P(X = 6) = 8k + 10k + 12k = 30k = 30 x 1/44 = 15/22