Correct Answer - C
Let
E
i
(
i
=
1
,
2
,
3
)
E
denote the event of drawing an even numbered card in ith draw and
O
i
O
denote the event of drawing an odd numbered card in I th(i=1,2,3) draw. Then,
Required probability
=
P
(
E
1
∩
O
2
O
3
)
∪
(
O
1
∩
E
2
∩
O
3
)
∪
(
O
1
∩
O
2
∩
E
3
)
=
=
P
(
E
1
∩
O
2
∩
O
3
)
+
P
(
O
1
∩
E
2
∩
O
3
)
+
P
(
O
1
∩
O
2
∩
E
3
)
=
=
P
(
E
1
)
P
(
O
1
)
P
(
O
3
)
+
P
(
O
1
)
P
(
E
2
)
P
(
O
3
)
+
P
(
O
1
)
P
(
O
2
)
P
(
E
2
)
=
=
7
15
×
8
15
×
8
15
+
8
15
×
7
15
×
8
15
×
8
15
×
7
15
=
=
3
×
7
×
8
2
15
3
=
448
1125
=
