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Three dice are thrown together. Find the probability of getting a total of at least 6.

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Three dice are thrown together. Find the probability of getting a total of at least 6. Select the correct answer from above options

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6⋅6⋅6=216 P1=1-P {(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,2,2),(2,2,1),(2,1,2),(1,1,3),(3,1,1),(1,3,1)} P(sum<6)=10/216<br> P(sum>6)=1-P(sum <6)<br> =1- 10 216 = 206 216 = 103 108 .

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