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Three dice are thrown together. The probability that the sum of the numbers appearing on them is 9, is A. 7 216 7 B. 47 54 47 C. 7 54 7 D. 7 9 7 Select the correct answer from above options

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Correct Answer - C Total number of elementary events = 6 3 = . Total number of ways of getting 9 as the sum = Coefficient of x 9 in ( x 1 + x 2 + x 3 + x 4 + x 5 + x 6 ) 3 x = Coefficient of x 6 in ( 1 + x + x 2 + x 3 + x 4 + x 5 ) 3 x = Coefficient of x 6 in ( 1 = x 6 1 − x ) 3 x = Coefficient of x 6 in ( 1 − x ) − 3 = . 6 + 3 − 1 C 3 − 1 = . 8 C 2 = 28 x ∴ ∴ Favourable number of elementary events =28. So, required probability = 28 216 = 7 54 =

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