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A bag contains 4 red and 4 black balls, another bag contains 2 red and 6 black balls. One of the two bags is selected at random and a ball is drawn fr

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A bag contains 4 red and 4 black balls, another bag contains 2 red and 6 black balls. One of the two bags is selected at random and a ball is drawn from the bag which is found to be red. Find the probability that the ball is drawn from the first bag. Select the correct answer from above options

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`P(B_1) = 1/2 ` `P(B_2) = 1/2` `P(R/B_1)= 4/8 = 1/2` `P(R/B_2) = 2/8 = 1/4` `P(B_1/R) = (P(B_1)P(R/B_1))/(P(B_1)P(R/B_1) + P(B_2)P(R/B_2))` `= (1/2)/(1/2 + 1/4) = (2/4)/(2/4+1/4) ` `= 2/3` Answer

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