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The unit vector to the points p1(0,1,0), p2(1,0,1), p3(0,0,1) is (a) (-j – k)/1.414 (b) (-i – k)/1.414 (c) (-i – j)/1.414 (d) (-i – j – k)/1.414 The question was posed to me in an online interview. The above asked question is from Position and Distance Vectors topic in chapter Vector Analysis and Applications of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Right choice is (a) (-j – k)/1.414 To explain: The cross product of p1, p2, p3 is a X b = -j – k and its magnitude is 1.414. The unit normal vector is given by, (-j – k)/1.414.

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