Question

The torque expression of a current carrying conductor is (a) T = BIA cos θ (b) T = BA cos θ (c) T = BIA sin θ (d) T = BA sin θ The question was posed to me in unit test. Query is from Magnetization in section Magnetic Forces and Materials of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

Answer 1

Right answer is (c) T = BIA sin θ Easy explanation: The torque is given by the product of the flux density, magnetic moment IA and the sine angle of the conductor held by the field. This gives T = BIA sin θ.