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The expression for velocity of a wave in the conductor is (a) V = √(2ω/μσ) (b) V = √(2ωμσ) (c) V = (2ω/μσ) (d) V = (2ωμσ) The question was posed to me by my college director while I was bunking the class. My doubt stems from Plane Waves in Good Conductor topic in division EM Wave Propagation of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Right option is (a) V = √(2ω/μσ) Best explanation: The velocity is the ratio of the frequency to the phase constant. In conductors, the phase constant is given by √(ωμσ/2). On substituting for β,ω in v, we get v = √(2ω/μσ) units.

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