Question

A circuit is given in the figure below. We can infer that ________ (a) The circuit follows Reciprocity Theorem (b) The circuit follows Millman’s Theorem (c) The circuit follows Superposition Theorem (d) The circuit follows Tellegen Theorem I have been asked this question in an interview. Asked question is from Advanced Problems on Reciprocity Theorem topic in section Useful Theorems in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct choice is (a) The circuit follows Reciprocity Theorem The explanation: Let us consider this circuit, Equivalent Resistance REQ = 20 + [30 || (20 + (20||20))] = 20 + [30 || (20 + \(\frac{20×20}{20+20}\))] = 20 + [30 || (20+10)] = 20 + [30 || 30] = 20 + \(\frac{30 × 30}{30+30}\) = 20 + 15 = 35 Ω The current drawn by the circuit = \(\frac{200}{35}\) = 5.71 A Now, by using current division rule, we get, I1 = 1.43 A Again, let us consider this circuit, Equivalent Resistance, REQ = [[((30 || 20) + 20) || 20] + 20] = \(\Big[\Big[\left(\left(\frac{30 × 20}{30+20}\right) + 20\right) || 20\Big] + 20\Big]\) = [[(12 + 20) || 20] + 20] = [[32 || 20] + 20] = \(\Big[\left(\frac{32 × 20}{32+20}\right) + 20\Big]\) = [12.31 + 20] = 32.31 Ω The current drawn by the circuit = \(\frac{200}{32.31}\) = 6.19 A Now, by using current division rule, we get, I2 = 1.43 A. Since I1 = I2, the circuit follows Reciprocity Theorem.