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In the circuit given below, the capacitor is initially having a charge of 10 C. 1 second after the switch is closed, the current in the circuit is ________ (a) 14.7 A (b) 18.5 A (c) 40.0 A (d) 50.0 A I got this question by my school teacher while I was bunking the class. My question comes from Calculation of I(0+), di/dt(0+), d2I/dt2(0+) in Circuits Involving both Capacitor and Inductor topic in division Application of the Laplace Transform in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Right answer is (a) 14.7 A The best explanation: Using KVL, 100 = R\frac{dq}{dt} + \frac{q}{C} 100 C = RC\frac{dq}{dt} + q Or, \int_{q_o}^q \frac{dq}{100C-q} = \frac{1}{RC} \int_0^t \,dt 100C – q = (100C – qo)e^-t/RC I = \frac{dq}{dt} = \frac{(100C – q_o)}{RC} e^{-1/1} ∴ e^-t/RC = 40e^-1 = 14.7 A.

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