Question

In the circuit shown below find the power dissipated by 2Ω resistor. (a) 16.24 (b) 17.24 (c) 18.24 (d) 19.24 This question was posed to me during an internship interview. My query is from Nodal Analysis in portion Steady State AC Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct answer is (c) 18.24 To explain I would say: Applying nodal analysis at node ‘a’, (Va-20∠30^o)/3+Va/(-j4)+Va/(2+j5)=0. On solving, Va = 16.27∠18.91⁰. Current in 2Ω resistor I2 = Va/(2+j5) = (16.27∠18.91^o)/(5.38∠68.19^o)=3.02∠-49.28^o. Power dissipated in 2Ω resistor P=I2^2 R=3.02^2×2 = 18.24W.