Question

Find the voltage drop across 6Ω resistor in the circuit shown below. (a) 6.58 (b) 7.58 (c) 8.58 (d) 9.58 The question was posed to me in an international level competition. Query is from Norton’s Theorem topic in chapter Useful Theorems in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct answer is (c) 8.58 For explanation I would say: The voltage across the 6Ω resistor is V = 1.43×6 = 8.58V. So the current and voltage have the same values both in the original circuit and Norton’s equivalent circuit.