Question

What is the steady state value of F (t), if it is known that F(s) = \frac{1}{(s+2)^2 (s+4)}? (a) \frac{1}{16} (b) Cannot be determined (c) 0 (d) \frac{1}{8} I got this question by my school teacher while I was bunking the class. This intriguing question originated from Problems on Initial and Final Value Theorem topic in section Application of the Laplace Transform in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Right option is (c) 0 To elaborate: The steady state value of F(s) exists since all poles of the given Laplace transform have negative real part. ∴F(∞) = lims→0 s F(s) = lims→0 \frac{s}{(s+2)^2 (s+4)} = 0.