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What is the steady state value of F (t), if it is known that F(s) = \frac{10}{(s+1)(s^2+1)} ? (a) -5 (b) 5 (c) 10 (d) Cannot be determined I have been asked this question in homework. This is a very interesting question from Problems on Initial and Final Value Theorem topic in division Application of the Laplace Transform in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Right answer is (d) Cannot be determined Explanation: The steady state value of this Laplace transform is cannot be determined since; F(s) is having two poles on the imaginary axis (j and –j). Hence the answer is that it cannot be determined.

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