Question

The current flowing through the resistance R in the circuit in the figure has the form 2 cos 4t, where R is ____________ (a) (0.18 + j0.72) (b) (0.46 + j1.90) (c) – (0.18 + j1.90) (d) (0.23 – 0.35 j) This question was addressed to me in semester exam. This interesting question is from Advanced Problems Involving Complex Circuit Diagram topic in chapter Network Theory and Complex Circuit Diagram of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct option is (d) (0.23 – 0.35 j) The explanation is: Inductor is not given, hence ignoring the inductance. Let I1 and I2 are currents in the loop then, I1 = \frac{2 cos⁡4t}{3} = 0.66 cos 4t Again, I2 = \frac{-j X 4 X 0.75 I_1}{3.92-2.56j} = (0.23 – 0.35j) cos 4