Equivalent of mongo shell UUID() in java mongo driver

Question

Following query is perfectly working in mongo shell. db.collection.find({ "_id" : UUID("87aa9ed6-8485-4517-8e90-08e521372e9a")}) I want to achieve same programmatically in java. I have tried below approaches but not getting any result. 1) collection.find(eq("_id", "87aa9ed6-8485-4517-8e90-08e521372e9a")); 2) `UUID uuid = UUID.fromString("87aa9ed6-8485-4517-8e90-08e521372e9a"); collection.find(eq("_id", uuid));` JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

You can use this for single UUID if you have a mongoTemplate defined Query query= new Query(); query.addCriteria(Criteria.where("_id").is(uuid)); mongoTemplate.findOne(query,YourObjectName.class); If you have multiple UUIDs you can use criteria orOperator Query query= new Query(); Criteria criteria=new Criteria(); List orCriteria=new ArrayList<>(); String[] splitId=ids.split(","); for(String id:splitId){ UUID uuid = UUID.fromString(id); orCriteria.add(Criteria.where("_id").is(uuid)); } criteria.orOperator(orCriteria.toArray(new Criteria[orCriteria.size()])); query.addCriteria(criteria); mongoTemplate.find(query,YourObjectName.class); Lmk if that works.