Create dict keys depending on the number of times the same value occurs

Question

I have the dict as below, if same value is found more than once then my dict key must be created with incremental numbering. TT = { "TYPE_1" : ['ERROR'], "TYPE_2": ['FATAL'], "TYPE_3" : ["TIME_OUT"], "TYPE_4" : ['SYNTAX'], "TYPE_5" : ['COMPILE'], } m1 = "ERROR the input is not proper" m2 = "This should have not occured FATAL" m3 = "Sorry TIME_OUT" m4 = "SYNTAX not proper" m5 = "u r late its TIME_OUT" The value "TIME_OUT" occur twice in the search. count = 0 for key in TT.keys(): print(key) Key_1 = key while key_1 in TT: count = count+1 key_1 = key + "_{}".format(count) The above code gives error Key_1 not defined. Expected OUTPUT: if same value is occuring more than once then the dict key should be created with incremental numbering "TYPE_3_1" : ["TIME_OUT"], TT = { "TYPE_1" : ['ERROR'], "TYPE_2": ['FATAL'], "TYPE_3" : ["TIME_OUT"], "TYPE_3_1" : ["TIME_OUT"], "TYPE_4" : ['SYNTAX'], "TYPE_5" : ['COMPILE'], } Select the correct answer from above options

Answer 1

There can be an efficient way of solving this if you can rethink some of a data structure but if that is not an option you may be able to try this. inputs = ["ERROR the input is not proper", "This should have not occurred FATAL", "Sorry TIME_OUT", "SYNTAX not proper", "u r late its TIME_OUT"] basic_types = { "TYPE_1" : ['ERROR'], "TYPE_2": ['FATAL'], "TYPE_3" : ["TIME_OUT"], "TYPE_4" : ['SYNTAX'], "TYPE_5" : ['COMPILE'], } type_counts = {} results = {} for sentence in inputs: for basic_type in basic_types: if basic_types.get(basic_type)[0] in sentence: type_counts[basic_type] = type_counts.get(basic_type, 0) + 1 if type_counts[basic_type] == 1: results[basic_type] = [basic_types.get(basic_type)[0]] else: results[basic_type+"_{}".format(type_counts[basic_type] - 1)] = [basic_types.get(basic_type)[0]] print(results) Improve your knowledge in data science from scratch using Data science online courses