Correct Answer - 16.23M
68%
by mass that 68g
of HNO3
is present in 100g
of solution.
Volume of solution =
Massofsolution
Densityofsolution
=
100g
1.50gmL-1
=66.5cm3=0.65L
Molar mass, MwB
of HNO3=1+14+48=63
Molarity=
WA
MwB×V
=
68g
63gmol-1×0.0665
=16.23M