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The conductivity of `0.20M` solution of `KCl` at `298K` is `0.0248 S cm^(-1)` . Calculate its molar conductivity.

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The conductivity of 0.20M solution of KCl at 298K is 0.0248Scm-1 . Calculate its molar conductivity. Select the correct answer from above options

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Correct Answer - 124scm2mol-1 ∧m= k×1000 Molarity = 0.0248Scm-1×1000cm2L-1 0.20mL-1 =124Scm2mol-1

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